Formulas and decision rules
Absolute value is distance from zero. Its piecewise definition is:
Direct equation roots
For a ≠ 0 and c > 0:
Center and radius
For |ax+b| < c, the solution lies within radius c/|a| of center −b/a. Greater-than relations select the outside rays.
Inside: AND
Outside: OR
Threshold decision table
| Relation | c < 0 | c = 0 | c > 0 |
|---|---|---|---|
| = | No solution | One root: u = 0 | Two cases: u = ±c |
| < | No solution | No solution | −c < u < c (AND) |
| ≤ | No solution | u = 0 | −c ≤ u ≤ c (AND) |
| > | All real x | u ≠ 0 | u < −c or u > c (OR) |
| ≥ | All real x | All real x | u ≤ −c or u ≥ c (OR) |
Method reference: OpenStax College Algebra 2e, §2.7 explains interval notation, inequality reversal, and absolute-value inequalities.
Worked examples for every case
=: two exact roots — |2x−3|=5
- Split:
2x−3=−5or2x−3=5. - Add 3:
2x=−2or2x=8. - Divide by 2:
x=−1orx=4. - Check: both substitutions give absolute value 5.
<: inside, open endpoints — |3x+1|<7
−7<3x+1<7.- Subtract 1:
−8<3x<6. - Divide by 3:
−8/3<x<2. - Interval:
(−8/3,2).
≤: inside, closed endpoints — |x−4|≤2
−2≤x−4≤2.- Add 4:
2≤x≤6. - Interval:
[2,6]; both boundaries are included.
>: outside, open endpoints — |x+2|>3
x+2<−3orx+2>3.- Subtract 2:
x<−5orx>1. - Interval:
(−∞,−5) ∪ (1,∞).
≥ and negative a — |−2x+4|≥6
−2x+4≤−6or−2x+4≥6.−2x≤−10or−2x≥2.- Divide by −2 and reverse both signs:
x≥5orx≤−1.
Fractional coefficient — |(3/4)x−1|=5/2
(3/4)x−1=−5/2or(3/4)x−1=5/2.(3/4)x=−3/2or(3/4)x=7/2.- Multiply by 4/3:
x=−2orx=14/3.
One solution and zero threshold — |x−3|=0
- An absolute value is zero only when its interior is zero.
x−3=0, sox=3.
No solution — |x|=−2
|x|≥0for every real x.- It cannot equal −2, so the solution set is
∅.
All real numbers — |x|≥0
- Absolute value is nonnegative by definition.
- The statement is true for every real x:
(−∞,∞).
Constant expression (a=0) — |0x+3|≥2
|0x+3|=3for every x.3≥2is true, so every real number works.
Common mistakes and quick corrections
Forgetting the negative case
|x|=4 gives x=4 and x=−4.
Using OR for an inside interval
|x|<3 means −3<x<3 (AND), not two outside rays.
Not reversing a sign
−2x>6 becomes x<−3 after division by −2.
Including strict endpoints
|x|<2 uses open endpoints: (−2,2).
Ignoring a negative threshold
|x|<−1 has no solution because |x|≥0.
Mixing brackets and parentheses
x≥2 is [2,∞): include 2 with a bracket, never bracket infinity.
Distance and tolerance applications
Comfortable temperature
Within 4°F of 72°F is |T−72|≤4, so 68≤T≤76.
Manufacturing tolerance
A part within 0.5 mm of 10 mm is |x−10|<0.5, so 9.5<x<10.5.
Distance from a landmark
At least 3 km from position 8 is |x−8|≥3, so x≤5 or x≥11.
Methodology, verification, privacy, and limits
Authorship: Starlight Tools. No independent credentialed mathematics reviewer is currently listed. The transparent calculation methodology follows the absolute-value and inequality rules cited above. Last methodology review: 31 August 2026.
Test evidence: the page’s automated self-checks cover two-root, one-root, no-solution, all-real-number, all five relations, negative outer and inner coefficients, fractional coefficients, zero and negative thresholds, constant expressions, and a right-side absolute-value group. A failed self-check is reported in the browser console rather than hidden.
Numbers are converted to reduced fractions and processed with BigInt arithmetic. Each numeric part is limited to 30 digits. Scientific and repeating-decimal notation are unsupported; use an exact fraction. Multiple absolute-value groups, nonlinear interiors, and variables outside the absolute-value group are outside this calculator’s one-group linear scope.
All solving happens locally in your browser. The calculator does not transmit or store your equation or inequality.
Absolute value solver FAQs
How do you solve an absolute value equation?
For positive c, split |u| = c into u = -c or u = c, then solve both linear equations. A zero threshold gives one case, and a negative threshold gives no real solution.
How do you solve an absolute value inequality?
For positive c, less-than relations become one compound inequality between -c and c joined by AND. Greater-than relations become two outside inequalities joined by OR. Inclusive symbols include the endpoints.
Why can an absolute value problem have no solution?
An absolute value cannot be negative. A constant absolute-value expression can also make the comparison false for every real x.
Can the solution be all real numbers?
Yes. For example, |x| ≥ 0 is always true. If a = 0, the expression is constant and the original comparison is either true for every real x or false for all of them.
Can I enter fractions and decimals?
Yes. Use integers, finite decimals, or fractions such as -3/4. Exact fractions are reduced automatically.
Is this absolute value solver private?
Yes. It solves locally in your browser and does not send or store the values you enter.